Question: For the circuit shown in the figure, the switch S is initially open and the capacitor is uncharged. The switch is then dosed at time t = 0. How many seconds after closing the switch will the energy stored in live capacitor be equal to 50.2 mJ?
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For the circuit shown in the figure, initially the switch is closed for a long time so that steady state has been reached. Then at t = 0, the switch is opened, due to which current in the circuit decays to zero.The heat generated in the inductor is [L = self inductance of inductor, r = resistance of inductor] :
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The magnitude of energy stored in the capacitor is: E = 12CΔV2 E = 1 2 C Δ V 2, so a change in potential difference will cause a change in energy stored. So when the switch is closed and let to equilibrium the resistors will be in series increasing total resistance causing the total current to be less than when it was when the switch was …
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(e) The amount of energy stored in or delivered by the inductor during the transient can be determined by calculating the energy stored in the inductor at different …
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Engineering. Electrical Engineering questions and answers. There is no energy stored in the circuit in (Figure 1) at the time the switch is closed. Choose the correct expression for …
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This is a situation where the simple rules are insufficient. You simply cannot analyze that circuit any more than you can solve x+2=x+3. What happens in the real world is that the inductor creates enough emf to form …
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Here''s the best way to solve it. 11) For the circuit shown in the figure, the switch S is initially open and the capacitor is uncharged. The switch is then closed at time t 0. How many seconds after closing the switch will the energy stored in the capacitor be equal to 50.2 mJ? 40 VT 90 uF 0.50 Mi2 (a) 81 s (b) 65 s (c) 97 s (d) 110 s (e) 130 s.
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Our expert help has broken down your problem into an easy-to-learn solution you can count on. Question: The switch in the circuit in (Figure 1) has been open a long time before closing at t = 0. At the time the switch …
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Here''s the best way to solve it. Use loop analysis on the circuit to set up the integrodifferential equation. There is no energy stored in the circuit shown in Fig. P12.31 at the time the switch is opened. Derive the integrodifferential equations that govern the behavior of the node voltages v_1 and v_2. Show that V_2 (s) = sI_g (s)/C [s^2 ...
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In the circuit shown in Fig. P 7.26, both switches operate together; that is, they either open or close at the same time. The switches are closed a long time before opening at t=0. a) How many microjoules of energy have been dissipated in the 12 kΩ resistor 2 ms
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Physics questions and answers. For the circuit shown in the figure, the switch S is initially open and the capacitor is uncharged. The switch is then closed at time t = 0, How many seconds after closing the switch will the energy stored in the capacitor be equal to 50.2 mJ? A) 81 s B) 65 s C) 97 s D) 110 s E) 130 s.
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This is the given circuit in the question. We are going to find the value of current. Just after closing the circuit. Just after closing the circuit Initially we are given that voltage across C1 capacitor as we let''s suppose that as we see one, then we can write it as we see
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Question: *6.48 After closing the switch in the circuit of Fig. P6.48 at t=0, it was reopened at t=1 ms. Determine iC(t) and plot its waveform for t≥0. Assume no energy was stored in either L or C prior to t=0. Figure P6.48: Circuit for Problem 6.48.
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CE Predict/Explain (a) When the switch is closed in the circuit shown in Figure $21-57$, does the total power dissipated in the circuit increase, decrease, or stay the same? (b) Choose the best explanation from among the following: I. Closing the switch adds one
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Step 1. When the switch is first turned on, the ... Questions 20-21 21. All switches are open, and there is no stored energy in the capacitor or the inductor. Switch S1 is closed. After the capacitor is fully charged, switch S1 is opened and switch S2 is closed. Which of the following expressions represents the maximum current in the LC circuit ...
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Answer: 81s. For the circuit shown in the figure, the switch S is initially open and the capacitor is. uncharged. The switch is then closed at time t = 0. How many seconds after closing the switch. will the energy stored in the capacitor be equal to 5 0. 2 m J ?
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Given circuit is in steady state. Potential energy stored in the capacitors is U. Now switch S is closed. Heat produced after closing the switch S is H. Find U H. Initially, the switch is open for a long time and capacitors are uncharged. If it is closed at t = 0,then. Figure given shows two identical parallel plate capacitors connected to a ...
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The energy stored in C1 and C2 before closing the switch can be calculated using the formula U = CV^2/2, while the energy stored in C1 and C2 after …
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The switch is closed at t = 0. a) Find V1 and V2 for t = 0+. b) Calculate the initial energy stored in the capacitors C1 and C2. c) Determine how much energy is stored in the capacitors as t approaches 0. d) Show that the total energy delivered to the 250 kÎ
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Electrical Engineering. Electrical Engineering questions and answers. After closing the switch in the circuit of Fig. P6.48 at t = 0, it was reopened at t = 1 ms. Determine i_C (t) and plot its waveform for t greaterthanorequalto 0. Assume no energy stored either L or C prior to t = 0. Determine the current responses i_L (t) and i_C (t) to a ...
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In the circuit below, no energy is stored in the circuit. The switch has been open for a long time before closing at t=0. Find the expression for the capacitor voltage vc(t) for t≥0.
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When we close the switch, what happens? Well, these lines where we see no resistors in circuit diagrams, that''s assumed to be resistance-less, so all of the current will actually flow that way. So, by closing this switch, you''re essentially removing …
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648 After closing the switch in the circuit of Fig P6.48 at it was reopened at t 1 ms. Determine ic(t) and plot its waveform for t 20. Assume no energy was stored in either L or C prior to t 0. ms 200 S2 ic 20 Vi 2.5 H 2.5 AuF …
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Question: 2). For the circuit shown in the figure, the switch S is initially open and the capacitor is uncharged. The switch is then closed at time t = 0. (a) Find charge across the capacitor at the instant when the energy stored in the capacitor is 50.2 m)? (b) How many seconds after closing the switch will the energy stored in the capacitor ...
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The inductor will have energy stored in the form of magnetic field. But there is no way/path to ground to discharge ... $begingroup$ You probably mean the switch, not the coil, is in a perfect vacuum. $endgroup$ – Thomas Fritsch Commented Jun 12, 2021 at 10: ...
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Electrical Engineering. Electrical Engineering questions and answers. In the circuit shown in (Figure 1), both switches operate together, that is, they either open or close at the same time. The switches are closed a long time before opening at t = 0. Part A How many microjoules of energy have been dissipated in the 12 k2 resistor 27 ms after ...
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I. Closing the switch adds one more resistor to the circuit. This makes it harder for the battery to supply current, which de-creases the power dissipated. II. The equivalent …
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Question: 6.48 After closing the switch in the circuit of Fig. P6.48 at 1 = 0, it was reopened at t 1 ms. Determine ic (t) and plot its waveform for t 0. Assume no energy was stored in either L or C prior to t0. t 1 ms 200 Ω ic 20 V (+ 2.5 H 2.5μF Figure P6.48: Circuit for Problem 6.48. Show transcribed image text. Here''s the best way to ...
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The values of the components in a simple series RC circuit containing a switch (see figure below) are C = 1.00 µF, R = 2.00 106 Ω, and e m f = 10.0 V. At the instant 14.8 s after the switch is closed, calculate the following. The circuit is a rectangular loop. The bottom side of the loop has a battery labeled emf ℰ, oriented with the ...
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VIDEO ANSWER: Despite this circuit, we are given resistance for this, that is 4 arms. The inductance is equal to 1 hand raised and the battery''s potential fram…
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Question: 2) There is no energy stored in the circuit shown below at the time the switch is opened. a. Derive the integrodifferential equations that govern the behavior of the node voltages v1 (t) and v2 (t). b. Find the Laplace transform of v2 (t), i.e. V2 (s). Need help with this one, thanks! There are 3 steps to solve this one.
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See Answer. Question: The switch in the circuit shown below has been open a long time before closing at t=0. At the time the switch closes, the capacitor has no stored energy. Find vo (t) for t≥0. Answer: vo (t)=0 V,t≥0. solve this problem WITHOUT using laplace transform. please match the answer with the given solution.
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VIDEO ANSWER: We are asked to calculate the time after the switch over is closed. The future is close to you, so let''s start to solve this problem It''s equal to 41 minus the power negative over Here. There were 40. I am concerned about this artist
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Suppose we have a simple RL circuit. At $t=0$, I close the switch so that current starts flowing in the circuit. When the steady state is achieved, current $i=frac{epsilon}{R}$ would be flowing in the circuit due to which an energy …
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Question: (1) In the circuit shown, before the switch is closed at time t = 0, no energy was stored either in the capacitor nor in the inductor. Immediately after closing the switch, the current in the 3-ohm resistor is given by: 3 10 mH 12 V 1 uF 20 (a) 2.4 A (b) 4.0 A (COA (d) 10.0 A (2) For the circuit shown, the expression for the current in the 50 mF capacitor
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